A 1.08×10−3 solution of quinine, a drug used in treating malaria, has a of 9.75. what is the Kb and pKb? - quinine more drug_uses
AB = quinine, and I suppose that is the pH value of 9.75.
pOH = 14 9.75 = 4.25
AB \\ \\ \\ \\ \\ \\ \\ \\ u0026lt -> A + B + --
[B] = 10 ^ -4.25 = 5.62 x 10 ^ -5 = [A +]
[AB] = 1.08 x 10 ^ -3 to 5.62 x 10 ^ -5 =, 001 M
KB = [b] [a +] / [AB] = (5.62 x 10 ^ -5) (5.62 x 10 ^ -5) / .001 = 3.16 x 10 ^ -6
pK =- log (Kb) =- log (3.16 x 10 ^ -6) = 5.50
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